Jury's array in symbolic way 1.0

[M, L] = jury(P,N)This function gives the Jury's array from a numerical or SYMBOLIC polynomial and includes the two special cases: (1) the first element of the second row of a block is zero; (b) a row of zeros (when there are roots on unit circle or reciprocal roots like (r,1/r). The symbolic results can be used to solve inequalities and obtain the stability intervals of symbolic vaiables.P Numerical or symbolic array of coeficients. In the case of symbolic variables it is necesarry to define them in workspace as: >> syms a b c ...N Digits to be considered zero a number. E.g, for N=5, 10^(-5) is considered a zero. By default, N=10M Jury's array without any simplification (e.g., with epsilon notation)L Simplified coefficients of first column and second row of each Jury's block (e.g., using the limit when epsilon tends to zero) that determines the place of roots: the number of roots outside the unit circle is equal to negative values in LExamples:1. syms z; P1=(z-1)*(z-2)*(z-0.3)*(z^2+1); P=sym2poly(P1); [M,L]=jury(P);2. syms z; P1=(z-0.1)*(z-0.2)*(z-0.3)*(z^2+1); P=sym2poly(P1); [M,L]=jury(P);3. syms a b; P=[1 a b 0.1]; [M,L]=jury(P);4. syms a; P=[1 a 1 0.1]; [M,L]=jury(P);5. P=[1 2 -1 -1 2 1]; [M,L]=jury(P);6. P=[ -1.21, -0.063, 5.3, -0.063, -1.21]; [M,L]=jury(P);7. syms z; P1=(z+1/2)*(z+2)*(z+0.5)*(z-0.8); P=sym2poly(P1); [M,L]=jury(P);

Requirements:	No special requirements
Platforms:	Matlab
Keyword:	Coefficients,  Column,  Define,  Epsilon,  N3d10,  Notation,  Simplification,  Simplified,  Workspace
Users rating:	0/10